Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Complete the following reactions :
(i) XeF 2 + H 2 →
(ii) XeF 6 + SiO 2 →
(iii) XeF 6 + SbF 5 →
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(i) XeF 2 + H 2 → Xe + 2HF
(ii) 2XeF 6 + SiO 2 → 2XeOF 4 + SiF 4 ;
2XeOF 4 + SiO 2 → 2XeO 2 F 2 + SiF 4
2XeO 2 F 2 + SiO 2 → 2XeO 3 (Explosive) + SiF 4
(iii) XeF 6 + SbF 5 → [XeF 5 ] + [SbF 6 ] – [Addition ionic product is formed )
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Covalency of oxygen cannot exceed 2 unlike sulphur which can show +4 or +6 because
Why do alkali metals form unipositive ions and impart characteristic colours to flame?
Comment on the order of mobilities of the alkali metal ions in aqueous solution : Li + < Na + < K +…
Why is KO 2 paramagnetic ?
Draw the structure of BeCl 2 in solid and vapour state.
Explain why in anion of Na 2 CO 3 all bond lengths are equal ?